ABCDABCD is a square with each side measuring 144 cm144 cm. MM is a point on CBCB such that CM=36 cmCM=36 cm. If NN is a variable point on the diagonal DBDB, find the least value of CN+MNCN+MN.
Answer:
180 cm180 cm
- Given, BC=144 cmBC=144 cm and CM=36 cmCM=36 cm
⟹BM=CB−CM=144−36=108⟹BM=CB−CM=144−36=108
Let's join AA to NN - Since △ADN≅△CDN[By SAS criterion]∴AN=CN[Corresponding sides of congruent triangles]
⟹ AN+MN=CN+NM
Observe that the value of AN+NM is least when ANM is a straight line. - Now, if ANM is a straight line, then △AMB is a right-angled triangle.
∴ by Pythagoras theorem,
From step 2, we have AN+MN=CN+NM.Least value of AN+NM =√AB2+BM2=√1442+1082=180 - Hence, the least value of CN+MN is 180 cm.